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a thin half ring of radius 20 centimetre is uniformly charged with a total charge q =0.7nc . the magnitude of the electric field strength at the centre of this half ring is? answer is
Already answered this qstn. as U have asked it twice,Reposting:We would need to calculate the electric field in both direction that is x and y respeectively.Therefore for x direcn.,dE = k’*k*dl*cos(thetha)/r^2where k’ be the charge densite over the semi arc.Now integerate both sides from theta 0 to pi.O integerating we get,Ex = (k*k’/r)(sinpi – sin0) = 0Similarly in y direcn. we get,dEy= k’*k*dl*cos(thetha)/r^2Integerating both sides,Ey = 2*K*K’/rNet electric field => E = Ey => 2KK’/rwhere K = 1/4pieand K’ = 0.7 x 10^-9/pi*0.2.
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