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A spherical shell of radius 10 cm is carrying a charge q. If electric potential at distances 5cm,10cm and 15cm from the centre of the spherical shell is V1,V2 and V3 respectively then (A)V1=V2>V3 (B)V1=V2 (C)V1>V2>V3 (D)V1

A spherical shell of radius 10 cm is carrying a charge q. If electric potential at distances 5cm,10cm and 15cm from the centre of the spherical shell is V1,V2 and V3 respectively then
(A)V1=V2>V3
(B)V1=V2
(C)V1>V2>V3
(D)V1
 

Grade:12

1 Answers

Arun
25763 Points
2 years ago
The potential inside a conductor is the same everywhere (if it wasn't, potential differences would exist and currents would flow internally until the charges redistributed and made the internal potential the same everywhere). 

So everywhere, including the surface, of the conductor is at a potential of V. 

Outside the sphere, the potential is given by k/r

This means the external potential is inversely proportional to distance from centre. 

15cm is 3/2 times bigger than the radius (10cm), so the potential at 15cm is 3/2 times smaller than the potential at the surface. 

Potential = V/(3/2) = (2/3)V
 
hence option a is correct

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