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Grade 11Electrostatics

a sphere of radius 1em has potential of 8000V then energy density near its surface will be

Profile image of Jayant Kumar
12 Years agoGrade 11
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1 Answer

Profile image of Arun Kumar
12 Years ago
D = Q/(4piR^2)

In general, surface charge density is the charge magnitude divided by the surface area (in this case, a sphere)