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Grade 12th passElectrostatics

a proton has an electrical potential energy of 2x10^-16 J relative to a nearby negatively charged plat. IF the proton is released from rest and accelerates towards the negative plate, how fast will it be going when it reaches the plate?

Eric

8 Years agoGrade 12th pass

2 Answers

Eshan

8 Years ago

Dear student,

When the proton reaches the negatively charged plate, it loses all its electrical potential energy into its kinetic energy(from Law of Conservation of Energy).

Hence $\dfrac{1}{2}mv^2=2\times 10^{-16}$

$\implies v=5\times 10^5m/s$

Khimraj

8 Years ago

The velocity will be given by

KE = poential energy

½mv² = 2*10^-16

So v = 5*10⁵m/s

Hope it clears..............................

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