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A positive charged particle q, when launched with some velocity 'v1' in a uniform field isfound to deviate by 60° in a certain time, such that its speed is halved. If -ve charged particle -2q , is launched with the same velocity 'v1' in the same field then after same time its speed is "v2". Mass of both particles is same then (v2)²/(v1)² would be :- (Initial velocities is is perpendicular to field)

A positive charged particle q, when launched with some velocity 'v1' in a uniform field isfound to deviate by 60° in a certain time, such that its speed is halved. If -ve charged particle -2q , is launched with the same velocity 'v1' in the same field then after same time its speed is "v2". Mass of both particles is same then (v2)²/(v1)² would be :-
(Initial velocities is is perpendicular to field)

Grade:12

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