A positive charged particle q, when launched with some velocity 'v1' in a uniform field isfound to deviate by 60° in a certain time, such that its speed is halved. If -ve charged particle -2q , is launched with the same velocity 'v1' in the same field then after same time its speed is v2. Mass of both particles is same then (v2)²/(v1)² would be :-
(Initial velocities is is perpendicular to field)
A positive charged particle q, when launched with some velocity 'v1' in a uniform field isfound to deviate by 60° in a certain time, such that its speed is halved. If -ve charged particle -2q , is launched with the same velocity 'v1' in the same field then after same time its speed is v2. Mass of both particles is same then (v2)²/(v1)² would be :-
(Initial velocities is is perpendicular to field)
(Initial velocities is is perpendicular to field)
random name , 3 Years ago
Grade 12
