A particle of mass 1 gram and charge 5 microcoulomb is thrown at a speed of 20 m per second against a uniform electric field strength 2 x 10 to the power 5 Newton per coulomb the distance travelled by the particle before coming to rest.a)0.1 b)0.2 c)0.3 d)0.4

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Khimraj · Answer

q = 5*10 -6 C. v = 20m/s. m = 10 -3 kg. E= 2*10 5 N/C. Let distance travelled is d. Then, qEd = (½)mv 2 . Then d = 0.2m. Hope it clears. If you like answer then please approve it.

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A particle of mass 1 gram and charge 5 microcoulomb is thrown at a speed of 20 m per second against a uniform electric field strength 2 x 10 to the power 5 Newton per coulomb the distance travelled by the particle before coming to rest.a)0.1 b)0.2 c)0.3 d)0.4

A particle of mass 1 gram and charge 5 microcoulomb is thrown at a speed of 20 m per second against a uniform electric field strength 2 x 10 to the power 5 Newton per coulomb the distance travelled by the particle before coming to rest.a)0.1 b)0.2 c)0.3 d)0.4

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