Electrostatics> A particle of mass 1 g and charge 1 micro...

A particle of mass 1 g and charge 1 microcoulomb is held at rest on a frictionless surface at a distance of 1 m from the fixed charge of 2 mC. if the particle is released, it will be repelled. the speed of the particle when it is at a distance of 10 m from the fixed charge is?

madhurya , 9 Years ago

Grade 12

2 Answers

ananthupotti

Force eperienced by the particle=kq1q2/r^2

=k*1*(10^-6)*2*(10^-3)/1

=18 N.

acceleration of particle=f/m=18/1*(10^-3)

a=18000m/s^2.

since V^2=U^2+2*a*S,

Initial velocity of particle=0 m/s,

thus, V^2=2*18000*10

V^2=360000

V=600m/s

Hope everything is clear!!

Last Activity: 9 Years ago

Kushagra Madhukar

Dear student,

Please find the solution to your problem.

We know, that electrostatic force is a conservative force.

Hence, the mechanical energy will remain conserved for the point charge

Hence, Ki + Ui = Kf + Uf

½ mu² + kq₁q₂/r₁ = ½ mv² + kq₁q₂/r₂

Hence, 0 + k x 10^-6 x 10^-3(1/1 – 1/10) = ½ x 10^-3 x v²

Hence, v² = 2 x 10³ x 9 x 10⁹ x 10^-9 x 9/10

Hence, v² = 16200

Hence, v = 127.28 m/s

Thanks and regards,

Kushagra

Last Activity: 5 Years ago

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Electrostatics> A particle of mass 1 g and charge 1 micro...

A particle of mass 1 g and charge 1 microcoulomb is held at rest on a frictionless surface at a distance of 1 m from the fixed charge of 2 mC. if the particle is released, it will be repelled. the speed of the particle when it is at a distance of 10 m from the fixed charge is?

madhurya , 9 Years ago

ananthupotti

Kushagra Madhukar

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