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a parallel plate capacitor is charged from a cell and then isolated from it the separation between the plates is now increased what happens to the field in the region

Samah Farooq , 8 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

When a parallel plate capacitor is charged and then isolated from the power source, the behavior of the electric field between the plates changes when the separation between them is increased. Let's break this down step by step to understand the underlying principles.

Understanding the Basics of a Parallel Plate Capacitor

A parallel plate capacitor consists of two conductive plates separated by an insulating material, known as a dielectric. When connected to a voltage source, charge accumulates on the plates, creating an electric field between them. The strength of this electric field (E) is given by the formula:

E = V/d

where V is the voltage across the plates and d is the separation between them.

Charging and Isolating the Capacitor

Once the capacitor is charged and then disconnected from the voltage source, it retains the charge (Q) on its plates. The voltage across the capacitor at this point can be expressed as:

V = Q/C

where C is the capacitance of the capacitor, which is determined by the area of the plates (A) and the separation distance (d) as follows:

C = ε₀(A/d)

Here, ε₀ is the permittivity of free space. When the capacitor is isolated, the charge remains constant, but the capacitance can change if the plate separation is altered.

Effects of Increasing Plate Separation

Now, let’s consider what happens when the separation between the plates is increased. Since the capacitor is isolated, the charge (Q) remains constant. However, as the distance (d) increases, the capacitance (C) decreases because:

C = ε₀(A/d)

As a result, the voltage (V) across the capacitor must increase to maintain the relationship defined by V = Q/C. This leads us to the following implications:

  • Electric Field Strength: The electric field (E) between the plates is still defined by the equation E = V/d. As the voltage increases while the distance increases, the electric field strength can actually remain constant or even increase, depending on the rate of change of voltage relative to distance.
  • Potential Energy: The energy stored in the capacitor, given by U = 1/2 QV, will also change. Since V increases while Q remains constant, the stored energy increases as well.

Summary of Changes in the Electric Field

In summary, when the separation between the plates of an isolated parallel plate capacitor is increased, the electric field in the region can either remain constant or increase, depending on the specific changes in voltage. The key takeaway is that the electric field is influenced by both the charge on the plates and the distance between them, leading to interesting dynamics in the behavior of capacitors in various configurations.

This understanding of capacitors is crucial in many applications, from simple electronic circuits to complex systems in electrical engineering. If you have any further questions or need clarification on any point, feel free to ask!

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