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# A figure show that a square of side "a" with charges +q kept on the all vertices. Find the potential at the centre of the square

Arun
25763 Points
2 years ago
Dear student

there is no image posted. Please check and reattach an image. I will be happy to help you.
Khimraj
3007 Points
2 years ago
potential at centre will be 4 times due to one charge at center
so V = 4*Kq/r = 4*K*q/(a/$\sqrt{2}$) = 4$\sqrt{2}$Kq/a
Hope it clears.
MonishGayen
35 Points
2 years ago
distance between the vertex and the centre of the square = 2-1/2a
potential at the centre of the square=4*2​1/2kq/(a)=21/2​kq/a
hope it helps you