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Grade 12Electrostatics

A cylinder of length 2a and radius 'a' has the x-axis as its axis. Its two ends (plane surfaces) are x = a and r = 3a respectively. Point charges +q and -9 are located at x = 2a and x = 0 respectively the axis of cylinder.

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4 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To analyze the electric field generated by the point charges located at different positions relative to the cylinder, we need to consider the contributions from each charge and how they interact with the geometry of the cylinder. Let's break this down step by step.

Understanding the Setup

We have a cylinder with a length of 2a and a radius of a, positioned along the x-axis. The ends of the cylinder are located at x = a and x = 3a. The point charges are situated at x = 2a (a positive charge +q) and at x = 0 (a negative charge -9). The goal is to determine the electric field at various points along the axis of the cylinder due to these charges.

Electric Field Due to Point Charges

The electric field (E) created by a point charge can be calculated using Coulomb's law, which states:

  • E = k * |q| / r²

where:

  • k is Coulomb's constant (approximately 8.99 x 10^9 N m²/C²),
  • q is the magnitude of the charge, and
  • r is the distance from the charge to the point where the electric field is being calculated.

Calculating the Electric Field at Different Points

Let's calculate the electric field at a point along the axis of the cylinder, say at x = a. We will consider the contributions from both charges:

1. Electric Field at x = a

For the positive charge +q located at x = 2a:

  • The distance from the charge to the point x = a is r = 2a - a = a.
  • The electric field due to this charge at x = a is:
    • E₁ = k * q / a² (directed away from the charge, since it is positive).

For the negative charge -9 located at x = 0:

  • The distance from this charge to x = a is r = a - 0 = a.
  • The electric field due to this charge at x = a is:
    • E₂ = k * 9 / a² (directed towards the charge, since it is negative).

Net Electric Field at x = a

Now, we can find the net electric field at x = a by combining the contributions from both charges:

  • Net E = E₁ - E₂ = (k * q / a²) - (k * 9 / a²).

This simplifies to:

  • Net E = k * (q - 9) / a².

Generalizing for Other Points

To find the electric field at other points along the axis of the cylinder, you would follow a similar approach:

  • Identify the distance from each charge to the point of interest.
  • Calculate the electric field due to each charge using Coulomb's law.
  • Sum the electric fields, taking into account their directions (positive or negative).

Visualizing the Electric Field

It can be helpful to visualize the electric field lines. The positive charge will create outward lines, while the negative charge will attract lines towards itself. The net electric field will depend on the relative strengths and distances of the charges.

Conclusion

By applying these principles, you can analyze the electric field at any point along the axis of the cylinder due to the given point charges. This method not only helps in understanding the specific scenario but also builds a foundation for tackling more complex electrostatic problems in the future.