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Grade 12th passElectrostatics

A circular wire loop of radius R carries a total charge q distributed uniformly over its length. A small length x(very very less than R) of the wire is cut off. Find the electric field at the centre due to the remaining wire.

Profile image of Aamina
9 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
ApprovedApproved Tutor Answer9 Years ago
Total charge given for loop = q.
Charge per unit length = q/2*pi*R
for dl element,
dq = qdl/2*pi*a.
Net electricf field at center due to that small length and reaining is:
0 = E + kdq/r^2
thus just put dq value now.
 

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