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A charged particle Q is placed outside a holow cone on the axis of the cone at a distance x from the centre of it's base. Electric flux linked with the slant surface of the cone due to the charge is

A charged particle Q is placed outside a holow cone on the axis of the cone at a distance x from the centre of it's base. Electric flux linked with the slant surface of the cone due to the charge is

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Grade:12

1 Answers

Parth
58 Points
3 years ago
Here charge is at the apex of the cone. So whatever electric field it’ll produce it’ll always be tangential to slant surface.
phi = flux =B.A = B*A*cos(theta), theta = angle between two vector. in this case, the electric field is perpendicular to slant height so the area
so angle = 90 degrees, and hence cos(90) = 0, so flux = 0, hence option A

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