badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

A charged particle Q is placed outside a holow cone on the axis of the cone at a distance x from the centre of it's base. Electric flux linked with the slant surface of the cone due to the charge is

7 months ago

Answers : (1)

Parth
58 Points
							
Here charge is at the apex of the cone. So whatever electric field it’ll produce it’ll always be tangential to slant surface.
phi = flux =B.A = B*A*cos(theta), theta = angle between two vector. in this case, the electric field is perpendicular to slant height so the area
so angle = 90 degrees, and hence cos(90) = 0, so flux = 0, hence option A
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details