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a charged particle of mass 2 mg remains freely in air in an elecrric field of strength 4 N/C directed upward. calculate the charge and determine its nature (g=10m/ s 2 )


4 years ago

## Answers : (3)

Raman Mishra
67 Points
							The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.Now, net force on the particle = Fnet = 0Taking the upward direction as positive, we have:                   Fnet = Fe – Fg = 0               => qE – mg = 0               => q = mg/E   Substituting $m=2\times 10^{-3}kg$                       E = 4N/C and g = 10m/s2 , we get:       $q=5\times 10^{-3}C$   Ans.

4 years ago
Xigroyr6
13 Points
							The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.Now, net force on the particle = Fnet = 0Taking the upward direction as positive, we have:                   Fnet = Fe – Fg = 0               => qE – mg = 0               => q = mg/E   Substituting m=2\times 10^{-3}kg                       E = 4N/C and g = 10m/s2 , we get:       q=5\times 10^{-3}C

3 years ago
Krish Gupta
75 Points
							Pretty easy, just do force balance and you are done.The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.Now, net force on the particle = Fnet = 0Taking the upward direction as positive, we have:                   Fnet = Fe – Fg = 0               => qE – mg = 0               => q = mg/E   Substituting $m=2\times 10^{-3}kg$                       E = 4N/C and g = 10m/s2 , we get:       $q=5\times 10^{-3}C$   Ans.

5 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions