badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

a charged particle of mass 2 mg remains freely in air in an elecrric field of strength 4 N/C directed upward. calculate the charge and determine its nature (g=10m/ s 2 )

4 years ago

Answers : (3)

Raman Mishra
67 Points
							
The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.
Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.
Now, net force on the particle = Fnet = 0
Taking the upward direction as positive, we have:
                   Fnet = Fe – Fg = 0
               => qE – mg = 0
               => q = mg/E
   Substituting m=2\times 10^{-3}kg 
                      E = 4N/C and g = 10m/s2 , we get:
       q=5\times 10^{-3}C   Ans.
4 years ago
Xigroyr6
13 Points
							The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.Now, net force on the particle = Fnet = 0Taking the upward direction as positive, we have:                   Fnet = Fe – Fg = 0               => qE – mg = 0               => q = mg/E   Substituting m=2\times 10^{-3}kg                       E = 4N/C and g = 10m/s2 , we get:       q=5\times 10^{-3}C
						
3 years ago
Krish Gupta
askIITians Faculty
75 Points
							
Pretty easy, just do force balance and you are done.
The given electric field should exert an upward force on the particle so that it cancels the gravitational force which acts on the particle in the downward direction.
Since the electric field is directed upwards, therefore the particle should be positively charged so that an upward force acts on it due to the electric field.
Now, net force on the particle = Fnet = 0
Taking the upward direction as positive, we have:
                   Fnet = Fe – Fg = 0
               => qE – mg = 0
               => q = mg/E
   Substituting m=2\times 10^{-3}kg 
                      E = 4N/C and g = 10m/s2 , we get:
       q=5\times 10^{-3}C   Ans.
5 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details