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Grade: 6
        
A charged oil drop is suspended in a uniform field of 3 x 104  v/m so that it neither falls nor rises. The charge on the drop will (Take the mass of the charge  = 9.9 x 10-15 kg  and g = 10 m/s2  )
 
(a) 1.6 x 10-18 C
(b) 3.2 x 10-18 C
(c) 3.3 x 10-18 C
(d) 4.8 x 10-18 C
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							

(c) At equilibrium, electric force on drop balances weight of drop.

qE = mg ? q = mg /E

q = 9.9 x 10-15 x 10 / 3 x 104 = 3.3 x 10-18 C
3 years ago
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