Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A charge Q is placed at the centre of a square. If electric field intensity due to the charge at the corners of the square is E1 and the intensity at the mid point of the side of square is E2, then the ratio of E1/E2 will be

A charge Q is placed at the centre of a square. If electric field intensity due to the charge at the corners of
the square is E1 and the intensity at the mid point of the side of square is E2, then the ratio of E1/E2 will be

Grade:12

1 Answers

Arun
25763 Points
2 years ago
The distance between the charge and the corner is a√2
distance between midpoint of side and charge is a/2
so net field is given by
kQ/r^2

e1=kQ/(1/2)a^2
e2=kQ/(1/4)a^2
e1/e2= 2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free