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Grade 6Electrostatics

A charge particle ‘q’ is shot towards another charged particle ‘Q’ which is fixed, with a speed ‘v’ . It approaches ‘q’ upto a closest distance r and then returns. If q were given a speed of ‘2v’ the closest distances of approach would be

Profile image of lokesh
12 Years agoGrade 6
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4 Answers

Profile image of Navjyot Kalra
12 Years ago
(d) ½ mv2 = kQq/r ? ½ m (2v)2 = kqQ/r’ ? r’ = r/4
Profile image of shubham
8 Years ago
as mentioned by navjyot 
all the kinetic energy is being completely converted into potential energy of system of two(both) particles
 
Profile image of swashna
7 Years ago
as per the kinetic energy formula.statement Navjyot is correct.
her the kinetic energy is totally converted into potential energy
Profile image of ankit singh
6 Years ago
= kqQ/r’ ? r’ =r/4(by the eneregy conservation equation).......................................2 = kQq/r ? ½ m (2v)2½ mv

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