To determine the value of charge \( q \) that maximizes the electrostatic repulsion between two charges \( q \) and \( Q - q \), we can use Coulomb's law, which describes the force between two point charges. The electrostatic force \( F \) between two charges is given by the formula:
Understanding the Forces Involved
The formula for the electrostatic force is:
F = k * |q1 * q2| / r²
Where:
- F is the electrostatic force between the charges.
- k is Coulomb's constant (approximately \( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)).
- q1 and q2 are the magnitudes of the charges.
- r is the distance between the charges.
Setting Up the Problem
In our case, we have two charges: \( q \) and \( Q - q \). The electrostatic force of repulsion \( F \) can be expressed as:
F = k * |q * (Q - q)| / r²
To maximize this force, we need to find the optimal value of \( q \) in terms of \( Q \).
Maximizing the Force
To find the maximum force, we can treat \( F \) as a function of \( q \) and differentiate it with respect to \( q \). First, we can rewrite the force equation:
F(q) = k * q * (Q - q) / r²
Next, we differentiate \( F \) with respect to \( q \):
dF/dq = k * (Q - 2q) / r²
Finding Critical Points
To find the critical points, we set the derivative equal to zero:
0 = Q - 2q
Solving for \( q \), we get:
2q = Q
q = Q/2
Verifying Maximum Condition
To ensure that this value of \( q \) indeed maximizes the force, we can check the second derivative:
d²F/dq² = -2k / r²
Since this second derivative is negative, it confirms that the function \( F(q) \) has a maximum at \( q = Q/2 \).
Conclusion
Thus, to maximize the electrostatic repulsion between the two charges, \( q \) should be equal to half of the total charge \( Q \). This means that if you divide the charge \( Q \) into two equal parts, each charge will be \( Q/2 \), leading to the maximum force of repulsion between them.