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A bullet of mass m and chage Q is fired towards a solid uniformly charged sphere of radius R and total charge +q. If it strikes the surface of sphere with speed u, find the minimum speed u so that it can penetrate through the sphere. (Neglect all resistant forces of friction acting on bullet except electrostatic forces.)

kunal gadhavi , 8 Years ago
Grade 11
anser 2 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
 
Force of repulsion = kQq/r^2
Force of bullet (F) = ma
These two force are equal
  • ma = kQq/r^2
  • a = kQq/mr^2
  • As bullet strike the sphere with speed u
  • S = u^2/2a = u^2kQq/2mr^2
  • 2R= u2mr2/2KQq
  • 4KQq/mR = u2
  • U =2√ KQq/mR
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

Yash Chourasiya

Last Activity: 4 Years ago

Hello Student

Total Energy of the system should be Conserve.

Total Energy at point 1 (On the surface) = Total Energy at point 2 (at the centre of sphere)
(K.E. + P.E.)1 = (K.E. + P.E.)2
(1/2mu2+ kq2/R) = (0 + (3kq2)/2R)

For further solution please see the Attachment.
643-2338_Untitled.png

I hope this solution will help you.

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