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Grade 12Electrostatics

A block of mass m having charge q is placed on smooth horizontal table and is connected to a wall through an unstressed spring of spring constant k . A horizontal electric field is switched on. Find the amplitude of the resulting SHM on the block.

Shantanu

12 Years agoGrade 12

3 Answers

Arun Kumar

Approved Tutor Answer12 Years ago

Since you are sure that it is SHM.

I ll find the Amplitude.

$Eq-kx=ma\\=>Eq-kx=0 \, for\, a=0\\=>x=Eq/k$

Here you can see in the first expression that acceleration is proportional to -x that's why it is SHM

Thanks & Regards

Arun Kumar

IIT Delhi

Askiitians Faculty

Krish Gupta

6 Years ago

Since you are sure that it is SHM.

I’’ll find the Amplitude.

$Eq-kx=ma\\=>Eq-kx=0 \, for\, a=0\\=>x=Eq/k$

Here you can see in the first expression that acceleration is proportional to -x that's why it is SHM

Kushagra Madhukar

6 Years ago

Dear student,

Please find the attached solution to your problem.

$Eq-kx=ma\\=>Eq-kx=0 \, for\, a=0\\=>x=Eq/k$

a = -k/m * x + Eq/m

Since, a is directly proportional to – x hence, it is SHM.

Hope it helps.

Thanks and regards,

Kushagra

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