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Grade: 12th pass

                        

A 3x10 -6 F capacitor is charged to a potential of 300 V and a 2 x10 -6 F capacitor is charged to 200 V. The capacitors are then connected in parallel with plates of opposite polarity joined together. What amount of charge will flow when the plates are so connected?

5 years ago

Answers : (3)

Shubham Singh
199 Points
							
1.2 x 10-4 C of charge will flow
5 years ago
noogler
489 Points
							
can u plz exp...........
i didnt get it
5 years ago
Shubham Singh
199 Points
							
first of all calculate the initial charges on each capacitor(suppose q1 and q2)
then when they are connected together so charge will flow till they are at same potential.
let q be charge flown.
so, q1 – q = q2 + q
         c1          c2
5 years ago
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