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Grade 12th passElectrostatics

A 3x10^-6 F capacitor is charged to a potential of 300 V and a 2 x10^-6F capacitor is charged to 200 V. The capacitors are then connected in parallel with plates of opposite polarity joined together. What amount of charge will flow when the plates are so connected?

noogler

11 Years agoGrade 12th pass

3 Answers

Shubham Singh

11 Years ago

1.2 x 10^-4 C of charge will flow

noogler

11 Years ago

can u plz exp...........

i didnt get it

Shubham Singh

Approved Tutor Answer11 Years ago

first of all calculate the initial charges on each capacitor(suppose q₁ and q₂)

then when they are connected together so charge will flow till they are at same potential.

let q be charge flown.

so, q₁ – q = q₂ + q

c₁ c₂

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