2 metal balls of rad r are placed at very large d

Question

2 metal balls of rad r are placed at very large distance from each other. they are connercted by a coil of inductance l and a switch s. one sphere is given charge +q and switch is closed. after what time charge on sphere is reduced to half of its initial value?

Vikas TU · Accepted Answer

As the whole system is placed at ground the circuit becomes closed loop and hence from KVL,V – Ldi/dt – V’ = 0V = Ldi/dt + V’kq/r = Ldi/dt + 0 (initially)kq/r = L*d^2q/dt^2Ld^2q = (kq/rL)dt^2qLdq = (kqt/rL)dt q^2*L = k*q*t^2/r*Lt^2 = qrL^2/kt = root(qrL/k)put q = q/2t = root(qrL/2k) s

Electrostatics> 2 metal balls of rad r are placed at very...

2 metal balls of rad r are placed at very large distance from each other. they are connercted by a coil of inductance l and a switch s. one sphere is given charge +q and switch is closed. after what time charge on sphere is reduced to half of its initial value?

Ambarish Kumar Banerjee , 9 Years ago

Vikas TU

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Electrostatics> 2 metal balls of rad r are placed at very...

2 metal balls of rad r are placed at very large distance from each other. they are connercted by a coil of inductance l and a switch s. one sphere is given charge +q and switch is closed. after what time charge on sphere is reduced to half of its initial value?

Ambarish Kumar Banerjee , 9 Years ago

Vikas TU

LIVE ONLINE CLASSES

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