+91-87964 74404
FlagBACK
Question icon
Grade 12Electrostatics

2 capacitors of capacitance 2 micro F and 3 micro F are joined in series . Outer plate of first capacitor is at 1000 volt and outer plate of second capacitor is earthed . Now the potential on inner plate of each capacitor will be :

Profile image of Aastha
9 Years agoGrade 12
Answers icon

1 Answer

Profile image of Vikas TU
9 Years ago
Dear Student,
As Capacitor connected in series,
Then Common potential = (C1V1- C2V2)/(C1+C2)
C1 = 2 micro F C2= 3 micro F
V1 = 1000 V V2 = 0
Common Potential (V) =(C1V1)/(C1+C2)
                                      = 2000/5
                                      = 400 V.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

Other Related Questions on electrostatics

question mark
Electrostatics question based on earthing of spherical shell
electrostatics
1 Answer Available

Last Activity: 3 Years ago

question mark
an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
Find the value of q so that system remains in equilibrium.. figure attached below
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
Need to find the time taken for the dipole to come back to eqm
 
electrostatics
1 Answer Available

Last Activity: 4 Years ago