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An isolated conducting sphere whose radius R=1 metre has charge q=1/ 9 nc ( 1 divide 9) . The energy density at the surface of sphere is (in joule per metrecube)

(A) ε0/2 (B)ε0

(C)2ε0 (D)ε0/3

love singh , 15 Years ago
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anser 2 Answers
PARTH ARORA

energy density is  given by 1/2 f silen not E^2  where E is the electric field at the surface.

 

E= q^2 /( 4 pief silen not r^2)

 

where r is the radius of the conductor

put values and obtain ans

Last Activity: 15 Years ago
Abantika Routray
energy density formula =1/2epsilon*E^2                                                                                                                                           1/2*epsilon*(kq/r^2)^2                                                                                                                                                      1/2*epsilon(9*10^9*1/9*10^-9/1)^2
1/2*epsilon.1^2=epsion/2
 
 
 
 
                                    
Last Activity: 8 Years ago
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