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Two equal charges are saperated by a distance d A third charge place on a perpendicular bisector at x distance will experience maximum coloumb force when
Dear pallavi
F= k qQ/x2
horizontal component of this force will cancel each other and verticle component will be added
net force F'=2Fcosθ
cosθ = (x2-d2/4)1/2/x
so F' = 2kqQ(x2-d2/4)1/2/x3
for maximum force differential and put equal to zero
x= √3 d/4
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