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An electron and a proton are lying 10 cm apart The ratio of electrostatics force and gravitational force between them will be
Dear pallavi me =9.1 * 01-31 mp = 1.6 * 10-27 qe = -1.6 *10-19 qp =1.6 *10-19 Fg =Gmemp/(10)2 Fe =1/4∏ε qeqp/(10)2 Fe/Fg = (1/4∏ε) qeqp /Gmemp = 9*109 *(1.6 *10-19)2/(6.67*10-11 * 9.1 * 10-31 *1.6 * 10-27 ) =.23 * 10 40 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Dear pallavi
me =9.1 * 01-31
mp = 1.6 * 10-27
qe = -1.6 *10-19
qp =1.6 *10-19
Fg =Gmemp/(10)2
Fe =1/4∏ε qeqp/(10)2
Fe/Fg = (1/4∏ε) qeqp /Gmemp
= 9*109 *(1.6 *10-19)2/(6.67*10-11 * 9.1 * 10-31 *1.6 * 10-27 )
=.23 * 10 40
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best. Regards,Askiitians ExpertsBadiuddin
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