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If the potential of a capacitor having capacity 6 mF is increased from 10 V to 20 V, then increase in its energy will be
(a) 4 × 10-4 J
(b) 4 × 10-4 J
(c) 9 × 10-4 J
(d) 12 × 10-6 J
(c)
Capacitance of capacitor(C)=6 mF = 6 × 10-6 F;
Initial potential (V1) = 10 V and final potential (V2) = 20 V.
The increase in energy (?U)
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