Electrostatics> electrostatics...

an electron of mass M,initially at rest,moves through a certain distance in a uniform electric field in time T.A proton of mass m,also initially at rest, takes time t to move through an equal distance in this uniform electric field.Negelecting the effect of gravity,the ratio of t/T is nearly equal to...??

Ashik Rahman , 12 Years ago

Grade 12

2 Answers

Arun Kumar

$(1/2)a_{e}t_e^2=x_{e} \\(1/2)a_{p}t_p^2=x_{p} \\=>a_{e}t_e^2/a_{p}t_p^2=1 \\=>t_e^2/t_p^2=a_{p}/a_{e} \\=>t_e^2/t_p^2=M/m$
Acceleration inversely proportional to mass.
Thanks & Regards
Arun Kumar
IIT Delhi
Askiitians Faculty

Last Activity: 11 Years ago

Kushagra Madhukar

Dear student,

Please find the attached solution to your problem below.

Let the subscript of the term represent the particle.

Now, distance travelled by proton and electron is same under given constraints. (x_p = x_e)

Hence,

$(1/2)a_{e}t_e^2=x_{e} \\(1/2)a_{p}t_p^2=x_{p} \\=>a_{e}t_e^2/a_{p}t_p^2=1 \\=>t_e^2/t_p^2=a_{p}/a_{e} \\=>t_e^2/t_p^2=M/m$

Hence, t/T = t_e/t_p = (M/m)^½

Hope it helps.

Thanks and regards,

Kushagra

Last Activity: 5 Years ago

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Electrostatics> electrostatics...

Ashik Rahman , 12 Years ago

Arun Kumar

Kushagra Madhukar

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