A rod of length L has a total charge Q distributed uniformly along its length.It is bent in the shape of a semicircle.Find the magnitude of the electric field at the centre of curvature of the semicircle.

E = Q / 2ε₀L²

Amar Kumar

Askiitians Faculty

M.tech IIT Delhi

Please illustrate it with diagram.

Thanks & Regards

Amar Kumar

AskIITians Faculty

M. tech, IIT Delhi

Hello Student

Please see the solution in the attachment.


I hope this answer will help you.