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A rod of length L has a total charge Q distributed uniformly along its length.It is bent in the shape of a semicircle.Find the magnitude of the electric field at the centre of curvature of the semicircle.

dulendu , 12 Years ago
Grade 12
anser 4 Answers
Amar Kumar

E = Q / 2ε0L2

 

 

Amar Kumar

Askiitians Faculty

M.tech IIT Delhi

 


Last Activity: 12 Years ago
dulendu
Please illustrate it with diagram.
Last Activity: 12 Years ago
Amar Kumar

2196_94650_Untitled.jpg

 

 

 

Thanks & Regards

Amar Kumar

AskIITians Faculty

M. tech, IIT Delhi

Last Activity: 12 Years ago
Yash Chourasiya
Hello Student

Please see the solution in the attachment.
643-957_Untitled.png

I hope this answer will help you.
Last Activity: 5 Years ago
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