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Grade 12Electrostatics

In a certain region of space the potential is given by – V=k[2x2-y2+z2]. The electric field at the point (1,1,1) has magnitude.?

Profile image of Abhishek Parihar
13 Years agoGrade 12
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5 Answers

Profile image of Vikas TU
13 Years ago

E = - dV/dx

same with respecto y and z

now differentiate line wise and get the ansr.

Plz Approve!

Profile image of Anmol Dhingra
13 Years ago

aNS- 2 AND DIRN Z AXIS 

Profile image of SOURAV MISHRA
ApprovedApproved Tutor Answer13 Years ago

use partial differential to determine the components of the electric field strength vector.

the electric field strength vector is given by 

E = -k(4xi^ - 2yj^ + 2zk^)

therefore at the point (1, 1, 1) the magnitude of the electric field strength is (24)(1/2).

Profile image of Abhishek Parihar
13 Years ago

the ans is-

[(4)^2 +(2)^2+(2)^2]^1\2

i.e.

(24)^1/2

Profile image of Vishakha chandan
7 Years ago
magnt. of E:  k(2-1+1)  / under root of (2^2 +(-1)^2 +1^2) =2k/under root of 6......Explain: put1,1,1 in eqn ..upon... put coefficient of x^2,Y^2,Z^2 in denomenator with eqn ...