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In a certain region of space the potential is given by – V=k[2x2-y2+z2]. The electric field at the point (1,1,1) has magnitude.?

Abhishek Parihar , 11 Years ago
Grade 12
anser 5 Answers
Vikas TU

Last Activity: 11 Years ago

E = - dV/dx

same with respecto y and z

now differentiate line wise and get the ansr.

Plz Approve!

Anmol Dhingra

Last Activity: 11 Years ago

aNS- 2 AND DIRN Z AXIS 

SOURAV MISHRA

Last Activity: 11 Years ago

use partial differential to determine the components of the electric field strength vector.

the electric field strength vector is given by 

E = -k(4xi^ - 2yj^ + 2zk^)

therefore at the point (1, 1, 1) the magnitude of the electric field strength is (24)(1/2).

Abhishek Parihar

Last Activity: 11 Years ago

the ans is-

[(4)^2 +(2)^2+(2)^2]^1\2

i.e.

(24)^1/2

Vishakha chandan

Last Activity: 6 Years ago

magnt. of E:  k(2-1+1)  / under root of (2^2 +(-1)^2 +1^2) =2k/under root of 6......Explain: put1,1,1 in eqn ..upon... put coefficient of x^2,Y^2,Z^2 in denomenator with eqn ...

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