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In a certain region of space the potential is given by – V=k[2x2-y2+z2]. The electric field at the point (1,1,1) has magnitude.?

Abhishek Parihar , 12 Years ago
Grade 12
anser 5 Answers
Vikas TU

E = - dV/dx

same with respecto y and z

now differentiate line wise and get the ansr.

Plz Approve!

Last Activity: 12 Years ago
Anmol Dhingra

aNS- 2 AND DIRN Z AXIS 

Last Activity: 12 Years ago
SOURAV MISHRA

use partial differential to determine the components of the electric field strength vector.

the electric field strength vector is given by 

E = -k(4xi^ - 2yj^ + 2zk^)

therefore at the point (1, 1, 1) the magnitude of the electric field strength is (24)(1/2).

ApprovedApproved
Last Activity: 12 Years ago
Abhishek Parihar

the ans is-

[(4)^2 +(2)^2+(2)^2]^1\2

i.e.

(24)^1/2

Last Activity: 12 Years ago
Vishakha chandan
magnt. of E:  k(2-1+1)  / under root of (2^2 +(-1)^2 +1^2) =2k/under root of 6......Explain: put1,1,1 in eqn ..upon... put coefficient of x^2,Y^2,Z^2 in denomenator with eqn ...
Last Activity: 7 Years ago
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