No, as the minimum possible is 1.6 x 10^-19, which is the charge of an electron.
rest all
Approved Tutor Answer13 Years ago
no it cannot have this charge b''coz charge is quantizedwhich means it exist in whole no multiples of 1.6*10^(-19)
anurag hundal
13 Years ago
the least charge a body can have(without considering quarks) is -1.6 x 10^-19
Akash Kumar Dutta
13 Years ago
not poss since electronic charge=2 times the mentioned charge
a body cant have charge without the integral multiples of the charge of elec.
but quarks can have a charge=q/3...q=charge of electron
Tamana Sehgal
13 Years ago
q=ne
=> n=q/e = 0.8X10^(-19)/ 1.6X10^(-19) = 1/2
As, n is in fraction which is not possible. Hence, a body can''t have a charge of 0.8X10^(-19).
Abhishekh kumar sharma
13 Years ago
no
Anangaraj Saikia
7 Years ago
No it cant. A charged body cant have a charge of 0.8×10^(-19) bcoz charge can only be quantized in terms of n in which n stands for any integral values i.e, 0,1,2,... and the formula is given by q=ne.
To check whether the given charge is possible or not just divide the given charge by the charge of an electron.
The answer to the given question is 0.5 so it is not possible.
Thank you
Rahul
7 Years ago
No,because according to quantisation of charge charge cannot take arbitary values but only values that are integral multiples of the fundamental charge
ankit singh
6 Years ago
no it cannot have this charge b''coz charge is quantizedwhich means it exist in whole no multiples of 1.6*10^(-19)
the least charge a body can have(without considering quarks) is -1.6 x 10^-19
not poss since electronic charge=2 times the mentioned charge
a body cant have charge without the integral multiples of the charge of elec.
but quarks can have a charge=q/3...q=charge of electron