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If coulomb's law innvolves 1/(r cube) dependence, instead of

\r\n

1/(r square) would Gauss's Theorem be still the same?

Prachi Lepcha , 11 Years ago
Grade 12
anser 1 Answers
Prajwal kr

Last Activity: 11 Years ago

No. Any deviation from Couloumb''s law indicates the departure from Gauss''s law and vice versa.

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