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(Q) The charge per unit length of four quadrant of a ring of radius R is 2λ, -2λ, λ and -λ respectively. The electric field at the centre is

(a) −(λ ÷ 2∏ε R) î

(b) (λ ÷ 2∏ε R) j

(c) (√2λ ÷ 4∏ε R) î

(d) None of the above

SANATH mishra , 11 Years ago
Grade 12
anser 4 Answers
Abhishekh kumar sharma

Last Activity: 11 Years ago

a     -(λ\ 2pie e r)

Russell khajuria

Last Activity: 11 Years ago

answer is 1. considering the centre to be at origin. electric field can be easily found out due to each quadrant. the net field along y axis is zero

Adarsh Patankar

Last Activity: 11 Years ago

Answer is (a)

Electric field due to circular ring at the centre is 

(2kλ⁄R)sinθ/2 where θ is angle of that sector

and direction of electric field is along bisector of that angle

 

FITJEE

Last Activity: 11 Years ago

1st one is correctSmile

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