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(Q) The charge per unit length of four quadrant of a ring of radius R is 2λ, -2λ, λ and -λ respectively. The electric field at the centre is (a) −(λ ÷ 2∏ε R) î (b) (λ ÷ 2∏ε R) j (c) (√2λ ÷ 4∏ε R) î (d) None of the above

(Q) The charge per unit length of four quadrant of a ring of radius R is 2λ, -2λ, λ and -λ respectively. The electric field at the centre is


(a) −(λ ÷ 2∏ε R) î 


(b)   (λ ÷ 2∏ε R) j


(c)   (√2λ ÷ 4∏ε R) î


(d) None of the above

Grade:12

4 Answers

Abhishekh kumar sharma
34 Points
8 years ago

a     -(λ\ 2pie e r)

Russell khajuria
18 Points
8 years ago

answer is 1. considering the centre to be at origin. electric field can be easily found out due to each quadrant. the net field along y axis is zero

Adarsh Patankar
31 Points
8 years ago

Answer is (a)

Electric field due to circular ring at the centre is 

(2kλ⁄R)sinθ/2 where θ is angle of that sector

and direction of electric field is along bisector of that angle

 

FITJEE
43 Points
8 years ago

1st one is correctSmile

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