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(Q) The charge per unit length of four quadrant of a ring of radius R is 2λ, -2λ, λ and -λ respectively. The electric field at the centre is
(a) −(λ ÷ 2∏ε R) î
(b) (λ ÷ 2∏ε R) j
(c) (√2λ ÷ 4∏ε R) î
(d) None of the above
a -(λ\ 2pie e r)
answer is 1. considering the centre to be at origin. electric field can be easily found out due to each quadrant. the net field along y axis is zero
Answer is (a)
Electric field due to circular ring at the centre is
(2kλ⁄R)sinθ/2 where θ is angle of that sector
and direction of electric field is along bisector of that angle
1st one is correct
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