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three capacitors c1=20mf c2=40mf c3=50mf are connected in series .if no capacitor can sustain more than 50v ,then the maximum potential difference between the two terminals X and Y is?

three capacitors c1=20mf  c2=40mf   c3=50mf are connected in series .if no capacitor can sustain more than 50v ,then the maximum potential difference between the two terminals X and Y is?

Grade:12

2 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
6 years ago
In series charges are same.

We get Q from here then we will get V by RHS.

Thanks & Regards
Arun Kumar
IIT Delhi
Askiitians Faculty
Kushagra Madhukar
askIITians Faculty 629 Points
10 months ago
Dear student,
Please find the solution to your problem below.
 
Let, the charge on each capacitor be q.
Now, Potential drop across a capacitor, V = Q/C
Hence, the potential drop across the given capacitors will be-
For C1, V1 = q/20
For C2, V2 = q/40
For C3, V3 = q/50
 
Now, V1 is the highest among all the individual voltages.
Its max value can reach upto 50 volts
Hence, q/20 = 50
or, q = 1000 mC
 
Hence, V1 = 50 V
V2 = 1000/40 = 25 V
V3 = 1000/50 = 20 V
 
Hence potential difference between x and y terminal, V  = V1 + V2 + V3
                                                                             = 50 + 25 + 20
                                                                             = 95 V
 
Thanks and regards,
Kushagra

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