A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air.
What will be the electric force between these two charges placed in these two different medium(air & water)?
Dielectric constant of water is k.

Question

ankit cool · Answer

f=1/4&prod;&epsilon; 0 q 1 q 2 /(h 1 +&radic;kh 2 )

gauhar singh · Answer

this calculation is not possible n requires concepts not taught in 12, n equivalent distance cannot be taken as it is conceptually incorrect

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A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air. What will be the electric force between these two charges placed in these two different medium(air & water)? Dielectric constant of water is k.

A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air.
What will be the electric force between these two charges placed in these two different medium(air & water)?
Dielectric constant of water is k.

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A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air. What will be the electric force between these two charges placed in these two different medium(air & water)? Dielectric constant of water is k.

A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air. What will be the electric force between these two charges placed in these two different medium(air & water)? Dielectric constant of water is k.

2 Answers

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A charge q1 is placed h1 height below a pond of water. Charge q2 is placed h2 height above the pond in air.
What will be the electric force between these two charges placed in these two different medium(air & water)?
Dielectric constant of water is k.