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Force between two charge
Dear Ravi, F = Qq/4πεr^2q , Q - two chargesr - distances between charges1/4πε - the constant of equation which is 9 x 10^9F = (2 x 10^-4)(8 x 10^-4)(9 x 10^9)/((0.3)^2)= 16 000 N Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple to download the toolbar…. So start the brain storming…. become a leader with Elite Expert League ASKIITIANS Thanks Aman Bansal Askiitian Expert
Dear Ravi,
F = Qq/4πεr^2q , Q - two chargesr - distances between charges1/4πε - the constant of equation which is 9 x 10^9F = (2 x 10^-4)(8 x 10^-4)(9 x 10^9)/((0.3)^2)= 16 000 N
Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple to download the toolbar….
So start the brain storming…. become a leader with Elite Expert League ASKIITIANS
Thanks
Aman Bansal
Askiitian Expert
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