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A non conducting rod of lenght l is pivoted at its centre along with a weight w at a distance of X from left end of the rod. At the end of rod are attached small conducting spheres with charge q (left end) and 2q (right end) which lie at distance r from the fixed charge charge Q below each. Find X=?

This question is from Dinesh's New Millenium Physics. I think something is wrong with the answer given in the text.

Kamal Bahadur , 13 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to analyze the forces acting on the rod due to the charges and the weight. The system consists of a non-conducting rod pivoted at its center, with a weight and charged spheres at either end. Let's break down the components step by step to find the distance X from the left end of the rod where the weight is placed.

Understanding the Setup

We have a rod of length "l" pivoted at its center. The left end of the rod has a charge "q," and the right end has a charge "2q." Below each charge, there is a fixed charge "Q" located at a distance "r." The weight "w" is placed at a distance "X" from the left end of the rod. The goal is to find the value of X that keeps the system in equilibrium.

Forces Acting on the Rod

In this scenario, we have two main forces acting on the rod:

  • The gravitational force due to the weight "w" acting downwards at a distance "X" from the left end.
  • The electrostatic forces due to the charges "q" and "2q" acting on the rod.

Calculating Electrostatic Forces

Using Coulomb's law, the electrostatic force between two point charges is given by:

F = k * |q1 * q2| / r²

Where "k" is Coulomb's constant. For the left end charge "q" and the fixed charge "Q," the force can be expressed as:

F1 = k * |q * Q| / r²

For the right end charge "2q," the force is:

F2 = k * |2q * Q| / r²

Torque Calculation

To maintain equilibrium, the sum of torques about the pivot must equal zero. The torque due to the weight "w" is:

Torque_w = w * (l/2 - X)

The torque due to the electrostatic forces can be calculated by considering the distances from the pivot:

  • For charge "q," the distance from the pivot is l/2.
  • For charge "2q," the distance from the pivot is also l/2.

Thus, the total torque due to the electrostatic forces is:

Torque_electric = F1 * (l/2) - F2 * (l/2)

Setting Up the Equation

For equilibrium, we set the sum of torques to zero:

w * (l/2 - X) = F1 * (l/2) - F2 * (l/2)

Substituting the expressions for F1 and F2, we get:

w * (l/2 - X) = (k * |q * Q| / r²) * (l/2) - (k * |2q * Q| / r²) * (l/2)

Solving for X

Now, we can simplify this equation to isolate X:

w * (l/2 - X) = (k * |q * Q| - 2k * |q * Q|) * (l/2) / r²

Rearranging gives:

X = l/2 - (k * |q * Q| / (2w * r²))

This equation provides the value of X in terms of the known quantities. Ensure that you substitute the correct values for "w," "q," "Q," and "r" to find the specific distance.

Final Thoughts

In summary, the equilibrium of the rod is maintained by balancing the gravitational force with the net electrostatic forces acting on it. By carefully analyzing the torques and forces involved, we can derive the necessary distance X from the left end of the rod. If you have any specific values or further questions about this problem, feel free to ask!

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