Electric field and electric potential

Question

The work of electric field done during the displacement of a negatively charged particle towards a fixed positively charged particle is 9J. As a result the distance between the charges has been decreased by half. What work is done by the electric field over the first half of this distance?

Ans: 3J

How we are getting this answer plz explain

arpan chandrashekhar · Accepted Answer

given:

kQq/(x/2) - kQq/x =9 where x is the intial distance. . . .

or kQq/x = 9J

to find is

KQq/(3/4*x) - kQq/x .... as the rdistance b/w the particles becomes 3/4*x as the particle approches by a quater*x

therefore it is kQq/3x =9/3 =3

Electrostatics> Electric field and electric potential...

venkata sreekanth , 13 Years ago

arpan chandrashekhar

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venkata sreekanth , 13 Years ago

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LIVE ONLINE CLASSES

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