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Figure shows a hollow sphere of inner radius R and outer radius 3R. the material of sphere is non-conducting. it has a uniform volume charge density σ. there is a spherical cavity in the volume of sphere which touches the outer and inner surface and has a radius R. what is the value of electric field inside this cavity?

[Ans: 7σ/(12ε) , where ε is the permittivity of free space]

i just want to know the process of solving this problem....

Rup Chitrak , 13 Years ago
Grade 12th Pass
anser 1 Answers
Sher Mohammad

Last Activity: 11 Years ago

use guass law, qin /e=sA/e

7s/(12e) , where e is the permittivity of free space

sher mohammad
b.tech, iit delhi
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