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two free protons are separated by a distance of 1m. if they are released , the kinetic energy of each proton when at infinite separation is
initial energy = kqq/r =kqq (as r= 1m)
final energy = kinetic energy + potential energy
= kinetic energy + 0 (as ptential energy of system is 0 at infinite distance)
ENERGY CONSERVATION
final kinetic energy of system = initial potentil energy of system
=kqq
hence kinetic energy of each proton = kqq/2
q is charge of proton and value of k is 9 X (10^9)
PLEASE APPROVE MY ANSWER IF YOU LIKED IT
at 1m separation potential energy =E= (1/4pi(epsilon-zero))e2, at infinite separation potential energy is zero and the two protons have same kinetic energy, equal to E/2,
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