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two free protons are separated by a distance of 1m. if they are released , the kinetic energy of each proton when at infinite separation is

eshita paul , 14 Years ago
Grade 12
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KARAN ACHARYA

Last Activity: 14 Years ago

initial energy = kqq/r =kqq        (as r= 1m)

final energy = kinetic energy + potential energy 

                  = kinetic energy  + 0      (as ptential energy  of system is 0 at infinite distance)

 

ENERGY CONSERVATION

final kinetic energy of system =  initial potentil energy of system 

                                          =kqq

hence kinetic energy of each proton = kqq/2

q is charge of proton and value of k  is 9 X (10^9) 

 

 

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Chetan Mandayam Nayakar

Last Activity: 14 Years ago

at 1m separation potential energy =E= (1/4pi(epsilon-zero))e2, at infinite separation potential energy is zero and the two protons have same kinetic energy, equal to E/2,

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