the force between two chargesplaced in an air distance \"r\"apart is \"f\".then the force between the two chrages if a dielectric having k=4 thickness r/2 is introduced between tehy charges is

Dear Shivani

Distance in dielectric is √k times of the thickness of dielectric medium

equivalent distance= r/2 + r/2 * √4 = 3r/2

force will become 4f/9

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