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Two positive charges +Q are held fixed a distance d apart. A particle of negative charge -q is placed midway between them, perpendicular to the line joining them .At what point along perpendicular bisector will it experience maximum force

Two positive charges +Q are held fixed a distance d apart. A particle of negative charge -q is placed midway between them, perpendicular to the line joining them .At what point along perpendicular bisector will it experience maximum force

Grade:12

2 Answers

Dipanwita Bhattacharjee
32 Points
12 years ago
It should be placed at a distance of d/2 from the mid-point along the perpendicular bisector joining the 2 charges.

Reason: the -ve charge will experience maximum force if it is kept on the perpendicular bisector such that the line joining it & the +ve charges makes an angle of 45 degree with the line joining the two +ve charges.

 

If the -ve charge is kept at the mid point of the line joining the two charges the net force will be 0, bcoz the force experienced by the -ve charge due to the two +ve charges will be equal and in the opposite direction.

Nimon B
63 Points
12 years ago

It will experience max force only when it is kept in mid of the charges and on the line joining them....as if you keep them anywhere else on tne bisector..... the parallel components will always cancel.... and you'll get only the cos components..........Smile

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