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a thin metallic spherical shell contains a charge Q on it. a point charge q is placed at de centre of de shell and another charge q" is placed outside it. all de 3 charges r +ve.wat is de force on de charge at de centre?wat is de force on de central charge due to de shell ?
Dear Nandan
This is the concept of electrostatic shielding. Electric field lines can not penetrate the mettalic shell and net force on charge q is zero.
Force on q due to q" will be towards left and for the net force to be zero the force by shell will be towards left but magnitude can not be calculated as distances are not given.
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
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force on the charge at cetrer = force bw shell & charge + force bw charge & charge
electric field inside a spherical shell is 0 , so F = qE = 0
force due to shell on charge at center is 0 ...
net force = force bw two charges = kq2/r2
force due to shel = 0
force is 0
as the resultant force exp by q due to the shell is 0 as electric feild due to the shell is 0 inside the shell
now due to electrostatic sheilding of the shell electric feild due to q'' is sheilded and hence the force on q due to q'' is also 0
thank you
Hello Nandan,
Krish Gupta
AskiitiansExpert-IIT
Hope it clears the doubt and I hope it gets approval.
The charge of q1 outside the shell is positive and the metal is observed to be in a spherical shape. A negative charge is produced as a result of the induced positive charge from outside. Always an electric field will be zero inside the shell and electrons will move if and only of the electric force is applied. The movement of electrons gets stopped when the electric field comes in from different directions. Thus the electric field becomes zero. So there will not any force on q.
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