what will be the graph of ofelectric field due to uniformly charged disc?????

Graph of the field is very complex and Jee level is nowhere near it 

you don't have to worry about it

just study it about the axis about the axis

Dear student,

where Q is the total charge and R is the radius of the disk. A ring of thickness da centered on the disk as shown has differential area given by

and thus a charge given by

The field produced by this ring of charge is along the x-axis and is given by the previous result:

The total field is given by simply integrating over a from 0 to R

The integral is actually 'perfect' and is given by

After substituting the limits, we get the final result:

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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Sagar Singh

B.Tech, IIT Delhi