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what will be the graph of ofelectric field due to uniformly charged disc?????

what will be the graph of ofelectric field due to uniformly charged disc?????


2 Answers

Pravin Sanap
29 Points
10 years ago

Graph of the field is very complex and Jee level is nowhere near it 

you don't have to worry about it

just study it about the axis about the axis

879 Points
10 years ago

Dear student,


where Q is the total charge and R is the radius of the disk. A ring of thickness da centered on the disk as shown has differential area given by

and thus a charge given by

The field produced by this ring of charge is along the x-axis and is given by the previous result:

The total field is given by simply integrating over a from 0 to R

The integral is actually 'perfect' and is given by

After substituting the limits, we get the final result:


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