The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V 3 ) + (beta)V 2 where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

Question

The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V 3 ) + (beta)V 2 where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

Sourabh Singh · Answer

For ideal gas PV =nRT, so LHS can be written as PV . Now find the realtion of P wrt V ie P = (alpha)(V 2 )+ (beta)V and it will be maximum at -(beta)/2*(alpha) You will get the value

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The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V 3 ) + (beta)V 2 where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V³) + (beta)V² where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

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The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V 3 ) + (beta)V 2 where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V3) + (beta)V2 where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....

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The temperature (T) of one mole of an ideal gas varies with its volume (V) as T = – (alpha)(V³) + (beta)V² where alpha and beta are positive constants. The maximum pressure of the gas during this process is …....