Electrostatic topic, please give the answer with explanation

Electrostatic topic, please give the answer with explanation

Priyam Chugh,
5 years ago

Grade:

×

FOLLOW QUESTION

We will notify on your mail & mobile when someone answers this question.

Enter email idEnter mobile number

1 Answers

Vasanth Chavan

34
Points

5 years ago

Electrostatics is the study of electromagnetic phenomena that occur when there are no moving charges—i.e., after a static equilibrium has been established. Charges reach their equilibrium positions rapidly because the electric force is extremely strong. The mathematical methods of electrostatics make it possible to calculate the distributions of the electric field and of the electric potential from a known configuration of charges, conductors, and insulators. Conversely, given a set of conductors with known potentials, it is possible to calculate electric fields in regions between the conductors and to determine the charge distribution on the surface of the conductors. The electric energy of a set of charges at rest can be viewed from the standpoint of the work required to assemble the charges; alternatively, the energy also can be considered to reside in the electric field produced by this assembly of charges. Finally, energy can be stored in a capacitor; the energy required to charge such a device is stored in it as electrostatic energy of the electric field.Coulomb’s lawStatic electricity is a familiar electric phenomenon in which charged particles are transferred from one body to another. For example, if two objects are rubbed together, especially if the objects are insulators and the surrounding air is dry, the objects acquire equal and opposite charges and an attractive force develops between them. The object that loses electrons becomes positively charged, and the other becomes negatively charged. The force is simply the attraction between charges of opposite sign. The properties of this force were described above; they are incorporated in the mathematical relationship known as Coulomb’s law. The electric force on a charge Q1 under these conditions, due to a charge Q2 at a distance r, is given by Coulomb’s law,Explanation of static electricity and its manifestations in everyday life.Explanation of static electricity and its manifestations in everyday life.Encyclopædia Britannica, Inc.Equation.ADVERTISEMENTThe bold characters in the equation indicate the vector nature of the force, and the unit vector r̂ is a vector that has a size of one and that points from charge Q2 to charge Q1. The proportionality constant k equals 10−7c2, where c is the speed of light in a vacuum; k has the numerical value of 8.99 × 109 newtons-square metre per coulomb squared (Nm2/C2). Figure 1 shows the force on Q1 due to Q2. A numerical example will help to illustrate this force. Both Q1 and Q2 are chosen arbitrarily to be positive charges, each with a magnitude of 10−6 coulomb. The charge Q1 is located at coordinates x, y, z with values of 0.03, 0, 0, respectively, while Q2 has coordinates 0, 0.04, 0. All coordinates are given in metres. Thus, the distance between Q1 and Q2 is 0.05 metre.Figure 1: Electric force between two charges (see text).Figure 1: Electric force between two charges (see text).Courtesy of the Department of Physics and Astronomy, Michigan State UniversityThe magnitude of the force F on charge Q1 as calculated using equation (1) is 3.6 newtons; its direction is shown in Figure 1. The force on Q2 due to Q1 is −F, which also has a magnitude of 3.6 newtons; its direction, however, is opposite to that of F. The force F can be expressed in terms of its components along the x and y axes, since the force vector lies in the xy plane. This is done with elementary trigonometry from the geometry of Figure 1, and the results are shown in Figure 2. Thus,Equation.in newtons. Coulomb’s law describes mathematically the properties of the electric force between charges at rest. If the charges have opposite signs, the force would be attractive; the attraction would be indicated in equation (1) by the negative coefficient of the unit vector r̂. Thus, the electric force on Q1 would have a direction opposite to the unit vector r̂ and would point from Q1 to Q2. In Cartesian coordinates, this would result in a change of the signs of both the x and y components of the force in equation (2).Equation.How can this electric force on Q1 be understood? Fundamentally, the force is due to the presence of an electric field at the position of Q1. The field is caused by the second charge Q2 and has a magnitude proportional to the size of Q2. In interacting with this field, the first charge some distance away is either attracted to or repelled from the second charge, depending on the sign of the first charge.