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Grade 11AIPMT

a projectile is travelling at 30` to the horizontal after 2s of its projection and horizontally after 1s more. Calculate the velocity of projection

Profile image of Prince kumar
8 Years agoGrade 11
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1 Answer

Profile image of Eshan
8 Years ago
After 3 seconds, the body is travelling horizontally.

Hence\dfrac{usin\theta}{g}=3
\implies usin\theta=30

Also,v_x(2s)=ucos\theta,v_y(2s)=usin\theta-gt=usin\theta-20

Since it travels at30^{\circ} to horizontal at this time,
\dfrac{v_y}{v_x}=\dfrac{30-20}{ucos\theta}=tan30^{\circ}=\dfrac{1}{\sqrt{3}}
\implies ucos\theta=10\sqrt{3}
\implies u=20\sqrt{3}m/s,\theta=60^{\circ}

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