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a bullrt of mass 20 g leaves rifle at an initial speed 100m/s and strikes a target at same level with speed 50 m/s the amount of work done by resistance of air is
Dear Harshita by work - energy theorem,initial KE - final KE = work performed against air resistanceInitial KE = 1/2 * m * vi^2 Final KE = 1/2 * m * vf^2Hence change = 1/2 * 20/1000 * (100^2 - 50^2) = 1/100 * 150 * 50 = 75 JSo work done by bulllet against air resistance = 75 JOr work performed by air to reduce the energy of bullet = 75 J Regards,Arun (AskIITians Forum Expert)
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