In triangle ABC the bisector of angle B intersects the side AC at D. A line parllel to AC intersects the line segments AB,DB,CB at points P,R,Q respectively. Then find AB*CQ

Question

SHAIK AASIF AHAMED · Answer

Hello student,
Please find the answer to your question below

In triangle ABC, BD is the bisector of angle B
Also from Basic Proportionality theorem
(AB/BC)=(AP/CQ)
From cross multiplication we get
AB*CQ=AP*BC

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In triangle ABC the bisector of angle B intersects the side AC at D. A line parllel to AC intersects the line segments AB,DB,CB at points P,R,Q respectively. Then find AB*CQ

In triangle ABC the bisector of angle B intersects the side AC at D. A line parllel to AC intersects the line segments AB,DB,CB at points P,R,Q respectively. Then find AB*CQ

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In triangle ABC the bisector of angle B intersects the side AC at D. A line parllel to AC intersects the line segments AB,DB,CB at points P,R,Q respectively. Then find AB*CQ

In triangle ABC the bisector of angle B intersects the side AC at D. A line parllel to AC intersects the line segments AB,DB,CB at points P,R,Q respectively. Then find AB*CQ

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on 10 grade maths

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