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E is the perpendicular on AD from O. We can show by side-side-side criteria that triangles OMBand OMC are congruent, hence angle OMC =90. So OE=MD={17^2-15^2}^1/2=8, andOM=ED=AD-AE=15-\sqrt{10^2-8^2}=9. Thus, BC^2=4BM^2=4(10^2-9^2)=76.
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Sumit
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