Grade 1010 grade maths
In a triangle ABC median AM=17,altitude AD=15 and the circum radius R=10
find BC square
1 Answer
Dear student,
E is the perpendicular on AD from O. We can show by side-side-side criteria that triangles OMBand OMC are congruent, hence angle OMC =90. So OE=MD={17^2-15^2}^1/2=8, andOM=ED=AD-AE=15-\sqrt{10^2-8^2}=9. Thus, BC^2=4BM^2=4(10^2-9^2)=76.
Regards
Sumit
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