Trigonometry
numberof real root of the equation secx+cosx=151/2
numberof real root of the equation secx+cosx=151/2
1 Answer
Yash Baheti
Hi
Please follow the steps to reach to the solution.
Convert all terms into COS. Form a quadratic in COS and then find its roots.
You will see that one of the roots will be grater than 1 which is not possible.
Now the no of solutions will depend upon the given interval of x. In ( 0 to 2pi ) we have 2 solutions.
Please follow the steps to reach to the solution.
Convert all terms into COS. Form a quadratic in COS and then find its roots.
You will see that one of the roots will be grater than 1 which is not possible.
Now the no of solutions will depend upon the given interval of x. In ( 0 to 2pi ) we have 2 solutions.
Other Related Questions on trigonometry
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
Last Activity: 3 Years ago
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
Last Activity: 4 Years ago
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
Last Activity: 4 Years ago
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥
trigonometry
Last Activity: 4 Years ago